請問(wèn)在這段代碼中,加密后的字母藏在哪里?

<script language="javascript">
var LoginTimes = 0;
var signal = "0";

var base64EncodeChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
var base64DecodeChars = new Array(
    -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
    -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
    -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63,
    52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1,
    -1,  0,  1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14,
    15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1,
    -1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,
    41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1);
function base64encode(str) {
    var out, i, len;
    var c1, c2, c3;
    len = str.length;
    i = 0;
    out = "";
    while(i < len) {
c1 = str.charCodeAt(i++) & 0xff;
if(i == len)
{
     out += base64EncodeChars.charAt(c1 >> 2);
     out += base64EncodeChars.charAt((c1 & 0x3) << 4);
     out += "==";
     break;
}
c2 = str.charCodeAt(i++);
if(i == len)
{
     out += base64EncodeChars.charAt(c1 >> 2);
     out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));
     out += base64EncodeChars.charAt((c2 & 0xF) << 2);
     out += "=";
     break;
}
c3 = str.charCodeAt(i++);
out += base64EncodeChars.charAt(c1 >> 2);
out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));
out += base64EncodeChars.charAt(((c2 & 0xF) << 2) | ((c3 & 0xC0) >>6));
out += base64EncodeChars.charAt(c3 & 0x3F);
    }
    return out;
}
function base64decode(str) {
    var c1, c2, c3, c4;
    var i, len, out;
    len = str.length;
    i = 0;
    out = "";
    while(i < len) {
/* c1 */
do {
     c1 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
} while(i < len && c1 == -1);
if(c1 == -1)
     break;
/* c2 */
do {
     c2 = base64DecodeChars[str.charCodeAt(i++) & 0xff];
} while(i < len && c2 == -1);
if(c2 == -1)
     break;
out += String.fromCharCode((c1 << 2) | ((c2 & 0x30) >> 4));
/* c3 */
do {
     c3 = str.charCodeAt(i++) & 0xff;
     if(c3 == 61)
  return out;
     c3 = base64DecodeChars[c3];
} while(i < len && c3 == -1);
if(c3 == -1)
     break;
out += String.fromCharCode(((c2 & 0XF) << 4) | ((c3 & 0x3C) >> 2));
/* c4 */
do {
     c4 = str.charCodeAt(i++) & 0xff;
     if(c4 == 61)
  return out;
     c4 = base64DecodeChars[c4];
} while(i < len && c4 == -1);
if(c4 == -1)
     break;
out += String.fromCharCode(((c3 & 0x03) << 6) | c4);
    }
    return out;
}
/*function getElById(sId)
{
if (document.getElByIdById)
{
  // standard
  return document.getElByIdById(sId);
}
else if (document.all)
{
  // old IE
  return document.all[sId];
}
else if (document.layers)
{
  // Netscape 4
  return document.layers[sId];
}
else
{
  return null;
}
}*/
/*start of HGW 2008.1.10 For A36D04370 FireFox 顯示 V100R001C02B013 by w00104696*/
function getElById(sId)
{
return getElement(sId);
}
function getElementById(sId)
{
if (document.getElementById)
{
  return document.getElementById(sId);
}
else if (document.all)
{
  // old IE
  return document.all(sId);
}
else if (document.layers)
{
  // Netscape 4
  return document.layers[sId];
}
else
{
  return null;
}
}
/*getElByName*/
function getElementByName(sId)
{    // standard
if (document.getElementsByName)
{
  var element = document.getElementsByName(sId);
  
  if (element.length == 0)
  {
   return null;
  }
  else if (element.length == 1)
  {
   return  element[0];
  }
  
  return element;  
}
}
function getElement(sId)
{
  var ele = getElementByName(sId);
  if (ele == null)
  {
   return getElementById(sId);
  }
  return ele;
}
/*end of HGW 2008.1.10 For A36D04370 FireFox 顯示 V100R001C02B013 by w00104696*/
function SubmitForm()
{
    var Form = getElById('LoginForm');
with (Form)
{
  if (Username.value == "")
  {
   alert("帳號不能為空");
   return false;
  }
  if (Password.value == "")
  {
   alert("密碼不能為空");
   return false;
  }
  var cookie = "Cookie=" + "UserName:" + Username.value + ":" + "PassWord:"
                + base64encode(Password.value) + ":id=-1;path=/";
  document.cookie = cookie;
  location.replace("/login.cgi");
  //Form.action = '/html/content.asp';
  return false;
}
}
</script>
<body>


/*end of HG_Support 2007.11.09 HG522V100R001C02B010 by wangxuting*/
</script>

代碼是用的base 64編碼來(lái)寫(xiě)的

加密方法我知道,可是想請教解密步驟,謝謝啦

你可以被稱(chēng)為高高手了。

看不懂

哎,看來(lái),只有自己去慢慢的摸索了

高人啊

高手高手高高手